Does anyone know the answer to this Trigonometry question?
Posted by: My Dream Vacations Post date: February 7th, 2010The question is this (exact wording- i don’t think it can be solved.):
An airplane flew with the wind for 2.5 hours and returned the same distance agianst the wind in 3.5 hours. If the cruising speed of the plane was a constant 360 mph in the air, how fast was the wind blowing?
Hint: If the wind is r miles per hour, then the plane travels at (360+r) mph with the wind and at (360-r) mph against the wind.
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February 7th, 2010 at 11:46 pm
d = r * t
Since the distance is the same coming and going you can use, “the speed time time going equals the speed times time coming” for the equation.
(360+r)2.5 = (360-r)3.5
Now just solve this for r.
bye for now.